3x^2=12/9

Solution for 3x^2=12/9 equation:

3x^2=12/9

We move all terms to the left:

3x^2-(12/9)=0

We add all the numbers together, and all the variables

3x^2-(+12/9)=0

We get rid of parentheses

3x^2-12/9=0

We multiply all the terms by the denominator


3x^2*9-12=0

Wy multiply elements

27x^2-12=0

a = 27; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·27·(-12)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*27}=\frac{-36}{54}
=-2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*27}=\frac{36}{54}
=2/3
$